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  • Please Solve RD Sharma Class 12 Chapter15 Tangents and Normals Exercise Fill in the blanks Question 14 Maths Textbook Solution.

Please Solve RD Sharma Class 12 Chapter15 Tangents and Normals Exercise Fill in the blanks Question 14 Maths Textbook Solution.

Answers (1)

Answer:

Equation of tangent is  y=3

Hint:

Tangent is parallel to X-axis so slope becomes 0

Given:

Given curve   y=x+\frac{4}{x^{2}}

To find:

We have to find the equation of the tangent to the given curve that is parallel to X-axis

Solution:

Given tangent is parallel to X-axis so slope is 0

                \Rightarrow \frac{d y}{d x}=0                                                                                                                                          … (i)

                Here   y=x+\frac{4}{x^{2}}                                                                                                                             … (ii)

On differentiate both side with respect to  x  we get

                \frac{d y}{d x}=1-\frac{8}{x^{3}}

Substituting the value of  \frac{dy}{dx}  in equation (i), we get

               \begin{aligned} &1-\frac{8}{x^{3}}=0 \\\\ &x^{3}=8 \\\\ &x=2 \end{aligned}

\because From (ii) we get  y=2+\frac{4}{4}=3

Hence equation of tangent is y= 3                                         [ \because equation of tangent y-3=0(x-2) ]

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