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Provide Solution For R.D.Sharma Maths Class 12 Chapter 15 Tangents and Normals Exercise 15 point 1 Question 20 Maths Textbook Solution.

Answers (1)

Answer:

            (a) \frac{1}{2}Is the correct option 

Hint:

        slope\left ( 1 \right )\times slope\left ( 2 \right )=-1

Given:

            y=2e^{x} And y=ae^{-x}

Solution:

y=2e^{x}                (1)

Differentiating w.r.t x, we get

\frac{dy}{dx}=2e^{x}

Again     y=ae^{x}                    (2)

Differentiating w.r.t x we get

\frac{dy}{dx}=ae^{x}

Since (1) and (2) intersect orthogonally

\begin{aligned} &\text { slope }(1) \times \operatorname{slope}(2)=-1 \\ &a e^{x} \times-a e^{-x}=-1 \\ &-2 a=-1 \\ &a=\frac{1}{2} \end{aligned}

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