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Provide Solution For R.D.Sharma Maths Class 12 Chapter 15 Tangents and Normals Exercise Multiple Choice Questions Question 7 Maths Textbook Solution.

Answers (1)

Answer:

           \left ( b \right )\left ( \frac{1}{4}, \frac{1}{2}\right )

Hint:

         Use slop of the tangent m=\tan \theta

Given:

              The curve y^{2}=x

Solution:

\frac{dy}{dx}=Slope of the tangent at that point of the curve

Given curve is x=y^{2}

Keep y=athen x=y^{2}

Point \left ( a^{2},a \right )

\begin{aligned} &\frac{d y}{d x}\left(y^{2}-x\right)=0 \frac{d y}{d x}=\frac{1}{2 y}=\frac{1}{2 a}=\tan \left(45^{\circ}\right) \\ &\Rightarrow a=\frac{1}{2}, a^{2}=\frac{1}{4} \end{aligned}

Point\left ( \frac{1}{4},\frac{1}{2} \right )

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