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Provide solution for RD Sharma maths class 12 chapter 10 Differentiation exercise Fill in the blanks question  14

Answers (1)

Answer: f^{1}\left(\frac{\pi}{4}\right)=\left(\frac{1}{\sqrt{2}}\right)

Hint:f^{1}(x)=\left(\begin{array}{cc} \sin x & 0 \leq x \leq \frac{\pi}{2} \\\\ -\sin x & \frac{\pi}{2}<x<\pi \end{array}\right)

Given: f(x)=|\sin x|

Solution:  

\begin{aligned} &f(x)=\left(\begin{array}{cc} \sin x & 0 \leq x \leq \frac{\pi}{2} \\\\ -\sin x & \frac{\pi}{2}<x<\pi \end{array}\right) \\\\ &f^{{}'}(x)=\left(\begin{array}{cc} \cos x & 0 \leq x \leq \frac{\pi}{2} \\\\ -\cos x & \frac{\pi}{2}<x<\pi \end{array}\right) \end{aligned}

\begin{aligned} f^{{}'} \frac{\pi}{2}=& \cos \frac{\pi}{4} \\\\ &=\frac{1}{\sqrt{2}} \end{aligned}

 

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