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  • Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Fill in the blanks question 5

Explain solution RD Sharma class 12 Chapter 27 Striaght Line in Space Exercise Fill in the blanks question 5

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Answer :    l=\frac{1}{\sqrt{3}}, m=\frac{1}{\sqrt{3}}, n=\frac{-1}{\sqrt{3}}

Hint : Use straight line equation

Given :  \frac{x-1}{l}=\frac{y-2}{m}=\frac{z+1}{n}  passes through the point ( -1 , 0 , 1)

             \frac{x-1}{l}=\frac{y-2}{m}=\frac{z+1}{n} \Rightarrow \frac{x-1}{1}=\frac{y-2}{1}=\frac{z+1}{-1}

                           

By using direction ratios of line

\begin{gathered} l=\frac{a}{\sqrt{a^{2}+b^{2}+c^{2}}}, m=\frac{b}{\sqrt{a^{2}+b^{2}+c^{2}}} \text { And } n=\frac{c}{\sqrt{a^{2}+b^{2}+c^{2}}} \\ \end{gathered}

\Rightarrow l=\frac{1}{\sqrt{3}}, m=\frac{1}{\sqrt{3}}, n=\frac{-1}{\sqrt{3}}

 

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