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Need solution for RD Sharma maths class 12 chapter 10 Differentiation exercise Fill in the blanks question  11

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Answer: f^{{}'}\left(\frac{\pi}{x}\right)=\left(\frac{1}{\sqrt{2}}\right)

Hint: f(x)=\left(\begin{array}{cc} \cos x & 0 \leq x \leq \frac{\pi}{2} \\\\ -\cos x & \frac{\pi}{2}<x<\pi \end{array}\right)

Given:f(x)=|\cos x|

Solution:  

        f(x)=|\cos x|

      f(x)=\left(\begin{array}{cc} \cos x & 0 \leq u \leq \frac{\pi}{2} \\\\ -\cos x & \frac{\pi}{2}<u<\pi \end{array}\right)

\begin{aligned} f^{{}'}(x) &=\left(\begin{array}{cc} -\sin x & 0 \leq x \leq \frac{\pi}{2} \\\\ \sin x & \frac{\pi}{2}<x<\pi \end{array}\right) \\\\ f^{1}\left(\frac{\pi}{2}\right) &=-\sin \frac{\pi}{2} \\ &=-\frac{1}{\sqrt{2}} \end{aligned}

 

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