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Need solution for RD Sharma maths class 12 chapter 10 Differentiation exercise Multiple choice question 11

Answers (1)

Answer:

        Does not exist

Hint:

        \sec ^{-1} \alpha is not defined

Given:

        \sec ^{-1}\left(\frac{1}{2 x^{2}+1}\right) \text { W.r.t } \sqrt{1+3 x} \text { at } x=-\frac{1}{3}

Solution:  

We know that \sec ^{-1} \alpha  is not defined for \alpha \in(-1,1)

Here for     x=-\frac{1}{3}, \frac{1}{2 x^{2}+1}=\frac{9}{11} \in(-1,1)

\therefore \sec ^{-1}\left(\frac{1}{2 x^{2}+1}\right) Is not defined at   x=-\frac{1}{3}

Derivative of   \sec ^{-1}\left(\frac{1}{2 x^{2}+1}\right)   does not exist at x=-\frac{1}{3}

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infoexpert26

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