Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 chapter Differentiation exercise 10.8 question 1 maths textbook solution

Please solve RD Sharma class 12 chapter Differentiation exercise 10.8 question 1 maths textbook solution

Answers (1)

Answer: 2 \sec ^{2}\left(x^{2}\right) \tan \left(x^{2}\right)

Hint:

\begin{aligned} &\text { Let } u=\sec ^{2}\left(x^{2}\right) ; v=x^{2} \\\\ &\frac{d u}{d v}=\frac{\frac{d u}{d x}}{\frac{d v}{d x}} \end{aligned}


Given:  \sec ^{2}\left(x^{2}\right) \text { w.r.t } x^{2}

Explanation:

\begin{aligned} &\text { Let } u=\sec ^{2}\left(x^{2}\right), v=x^{2} \\\\ &\frac{d u}{d x}=2 \sec \left(x^{2}\right)\left[\sec x^{2} \tan x^{2} \times 2 x\right] \end{aligned}

        =4 x \sec ^{2}\left(x^{2}\right) \tan \left(x^{2}\right)                    (chain rule)

\begin{aligned} &\frac{d v}{d x}=2 x \\\\ &\frac{d u}{d v}=\frac{\frac{d u}{d x}}{\frac{d v}{d x}}=\frac{4 x \sec ^{2}\left(x^{2}\right) \tan \left(x^{2}\right)}{2 x} \end{aligned}

       =2 \sec ^{2}\left(x^{2}\right) \tan \left(x^{2}\right)

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE extends single girl child scholarship registration deadline till November 20
anam-khan

CBSE reminds schools to submit registration data of Class 9, 11 students by October 16

Latest Question