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Need solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 25.

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Answer: \frac{1}{10}

Hint:P\left(\frac{S}{G}\right)=\frac{P(S \cap G)}{P(G)}

Given, S= Student chosen randomly studies in class XII

            G= Female student chosen randomly

 \begin{aligned} &P(G)=\frac{430}{1000} \\ &P(S \cap G)=\frac{43}{1000} \\ &P\left(\frac{S}{G}\right)=\frac{P(S \cap G)}{P(G)} \end{aligned}

                    \begin{aligned} =\frac{ \frac{430}{1000}}{ \frac{430}{1000}} \\ = \frac{1}{10} \end{aligned}

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