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Need solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 16.

Answers (1)

Answer: \frac{2}{3}

Hint: Use,   P(B \mid A)=\frac{P(A \cap B)}{P(A)}

Given,

            A= No. is odd

            B=No. is prime

Solution:

Clearly,

\begin{aligned} &A=\{1,3,5\} \\ &B=\{2,3,5\} \\ &A \cap B=\{3,5\} \end{aligned}
            

 Required Probability P(B \mid A)=\frac{P(A \cap B)}{P(A)}

=\frac{2}{3}

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