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Please solve RD Sharma Class 12 Chapter 30 Probability Exercise Case Study Based  Question, question 2 sub question (v) Maths textbook solution.

Answers (1)

Answer:

            (c)

Hint:

            You must know rules of conditional probability and baye’s theorem,

Given:

            6% people are left handed with blood group O, 10% of those with other blood group are left handed, 30% of people have blood group O

Solution:

Probability that a randomly selected person is right handed

That person is not left handed P(\bar{E})=1-P(E)

\begin{aligned} &P(\bar{E})=1-P(E) \\ &=1-\left[P\left(E_{1}\right) \cdot P\left(\frac{E}{E_{1}}\right)+P\left(E_{2}\right) \cdot P\left(\frac{E}{E_{2}}\right)\right] \\ &=1-[0.3 \times 0.06+0.7 \times 0.1] \\ &=1-[0.018+0.07] \\ &=1-0.088 \\ &=1-\frac{88}{1000}=\frac{912}{1000}=\frac{114}{125} \end{aligned}

So, (c) is correct answer

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