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Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 14.

Answers (1)

Answer: =P(B \mid A)=\frac{P(A \cap B)}{p(A)}=\frac{1}{6}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given,

            A=No. appearing on second die is odd.

            B=The sum of the no. on two dice is 7.

Solution:

Clearly,

\begin{aligned} &A=\left\{\begin{array}{l} (1,1),(1,3),(1,5),(2,1),(2,3),(2,5), \\ (3,1),(3,3),(3,5),(4,1),(4,3),(4,5) \\ (5,1),(5,3),(5,5),(6,1),(6,3),(6,5) \end{array}\right\} \\ &B=\{(2,5),(5,2),(3,4),(4,3),(1,6),(6,1)\} \\ &A \cap B=\{(2,5),(4,3),(6,1)\} \end{aligned}            

Required Probability =P(B \mid A)=\frac{P(A \cap B)}{p(A)}=\frac{1}{6}

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