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  • Please solve RD Sharma class 12 chapter Probability exercise 30.1 question 5 maths textbook solution

Please solve RD Sharma class 12 chapter Probability exercise 30.1 question 5 maths textbook solution

Answers (1)

Answer:

 \frac{1}{6}

Hint:

Find all the possibilities of getting 4 on third toss.

Given, that 6 and 5 appear respectively on the first two tosses.

So, let

           A         =    Event for getting 4 on third toss

   =   { (1,1,4), (1,2,4), (1,3,4), (1,4,4), (1,5,4), (1,6,4),

        (2,1,4), (2,2,4), (2,3,4), (2,4,4), (2,5,4), (2,6,4),

        (3,1,4), (3,2,4), (3,3,4), (3,4,4), (3,5,4), (3,6,4),

        (4,1,4), (4,2,4), (4,3,4), (4,4,4), (4,5,4), (4,6,4),

        (5,1,4), (5,2,4), (5,3,4), (5,4,4), (5,5,4), (5,6,4),

        (6,1,4), (6,2,4), (6,3,4), (6,4,4), (6,5,4), (6,6,4) }

Now, let

B           =   Event of getting 6 on first and 5 on second

             = (6,5,1), (6,5,2), (6,5,3), (6,5,4), (6,5,5), (6,5,6),

Now,

A ∩ B       = (6,5,4)

Therefore,

\begin{aligned} &\text { Probability }=\frac{n(A\cap B)}{ n(B)}\\ &=\frac{1}{6} \end{aligned}

Posted by

Gurleen Kaur

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