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Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 12.

Answers (1)

Answer: \frac{2}{5}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given,

            A= 4 appears on the die at least once

            B=The sum of the numbers on two dice is 6

Solution:

\begin{aligned} &\mathrm{A}=\left\{\begin{array}{l} (1,4),(2,4),(3,4),(4,1),(4,2),(4,3), \\ (4,4),(4,5),(4,6),(5,4),(6,4) \end{array}\right\} \\ &\mathrm{B}=\{(1,5),(5,1),(2,4),(4,2),(3,3)\} \\ &\mathrm{A} \cap \mathrm{B}=\{(2,4),(4,2)\} \end{aligned}

P(A) = 11
P(B) = 5

Required Probability 

\begin{aligned} &=P\left(\frac{A}{B}\right) \\ &=\frac{n(A \cap B)}{n(B)}=\frac{2}{5} \end{aligned}

                        

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