Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Answers (1)

Answer: 1,\frac{1}{2}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given, A= Son standing on one end

            B= Father standing in the middle

Solution:

Clearly,

  S=Total events

   \begin{aligned} &=\{\mathrm{MFS}, \mathrm{MSF}, \mathrm{FSM}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{A}=\{\mathrm{MFS}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \\ &\mathrm{A} \cap \mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \end{aligned}

(1) 

\begin{gathered} P\left(\frac{A}{B}\right)=\frac{n(A \cap B)}{n(B)} \\ =\frac{2}{2} \\ =1 \end{gathered}

(2)

\begin{gathered} P(B \mid A)=\frac{P(A \cap B)}{P(A)} \\ =\frac{2}{4} \\ =\frac{1}{2} \end{gathered}

 

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE announces deadline for Class 10, 12 direct admissions, subject change
anam-khan

CBSE warns about unauthorised sources offering ‘quick’ ways of getting duplicate marksheets, certificates
anam-khan

CBSE unveils 8 major changes for Class 10, 12 board exams; what students need to know

Latest Question