Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Answers (1)

Answer: 1,\frac{1}{2}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given, A= Son standing on one end

            B= Father standing in the middle

Solution:

Clearly,

  S=Total events

   \begin{aligned} &=\{\mathrm{MFS}, \mathrm{MSF}, \mathrm{FSM}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{A}=\{\mathrm{MFS}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \\ &\mathrm{A} \cap \mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \end{aligned}

(1) 

\begin{gathered} P\left(\frac{A}{B}\right)=\frac{n(A \cap B)}{n(B)} \\ =\frac{2}{2} \\ =1 \end{gathered}

(2)

\begin{gathered} P(B \mid A)=\frac{P(A \cap B)}{P(A)} \\ =\frac{2}{4} \\ =\frac{1}{2} \end{gathered}

 

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Supreme Court to hear plea against CBSE evaluation policy for Gulf Class 12 students on July 14
anam-khan

'Award grace marks': CBSE's July 28 supplementary exam sparks student outrage over college admissions
anam-khan

CBSE Class 12 supplementary exam 2026 on July 28; LOC submission starts

Latest Question