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Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 15.

Answers (1)

Answer: P(B \mid A)=\frac{P(A \cap B)}{p(A)}=\frac{1}{6}

 

Hint: Use, P(B \mid A)=\frac{P(A \cap B)}{p(A)}

Given,

            A= Prime number appears on second die

            B=The sum of the numbers on two dice is 7

Solution:

Clearly,

\begin{aligned} &A=\left\{\begin{array}{l} (1,2),(1,3),(1,5),(2,2),(2,3),(2,5), \\ (3,2),(3,3),(3,5),(4,2),(4,3),(4,5), \\ (5,2),(5,3),(5,5),(6,2),(6,3),(6,5) \end{array}\right\} \\ &B=\{(2,5),(5,2),(3,4),(4,3),(1,6),(6,1)\} \\ &A \cap B=\{(2,5),(5,2),(4,3)\} \end{aligned}

P(A) = 18
P(B) = 6

Required Probability  P(B \mid A)=\frac{P(A \cap B)}{p(A)}=\frac{1}{6}

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