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Provide solution for RD Sharma Maths Class12 Chapter 30 Probability Exercise Fill in the Blanks Question, Question 3.

Answers (1)

Answer:   \frac{10}{9}

Given:

If A and B are two events such that P(\overline{A}\cup \overline{B})=\frac{2}{3}  and
P(A\cup B)=\frac{5}{9}

 Then P(\overline{A})+P(\overline{B})= ....

Hint:

Using P(\overline{A})=1-P(A)

Explanation:

Let A and B be the two events.

\begin{gathered} P(\bar{A} \cup \bar{B})=\frac{2}{3} \\ P(\overline{A \cap B})=\frac{2}{3} \\ \Rightarrow 1-P(A \cap B)=\frac{2}{3} \\ \Rightarrow P(A \cap B)=1-\frac{2}{3} \\ \Rightarrow P(A \cap B)=\frac{1}{3} \\ P(A \cup B)=\frac{5}{9} \text { (given) } \end{gathered}
Also ,

\begin{aligned} &\begin{aligned} \mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}}) &=(1-\mathrm{P}(\mathrm{A}))+(1-\mathrm{P}(\mathrm{B})) \\ &=1-\mathrm{P}(\mathrm{A})+1-\mathrm{P}(\mathrm{B}) \end{aligned} \\ &=2-[\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})] \\ &\Rightarrow \mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})=2-(\mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})) \end{aligned}

Now we know,

\begin{aligned} &\frac{5}{9}=2-(\mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}}))-\frac{1}{3} \\ &\Rightarrow \mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})=2-\frac{5}{9}-\frac{1}{3} \\ &\Rightarrow \mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})=\frac{18-5-3}{9}=\frac{10}{9} \\ &\Rightarrow \mathrm{P}(\overline{\mathrm{A}})+\mathrm{P}(\overline{\mathrm{B}})=\frac{10}{9} \end{aligned}

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