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  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (ii).

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (ii).

Answers (1)

Answer: =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{3}{7}

 Hint:  \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given, A=At least two heads

            B=At most two heads

Solution:

Clearly, 

S=\{(H H H),(H H T),(H H T),(T T H),(T T T),(H T H),(T H H),(T T H)\}

\begin{aligned} &\mathrm{A}=\{(\mathrm{HHH}),(\mathrm{HTH}),(\mathrm{THH}),(\mathrm{HHT})\} \\ &\mathrm{B}=\{(\mathrm{TT}),(\mathrm{HTH}),(\mathrm{HTT}),(\mathrm{THT}),(\mathrm{THH}),(\mathrm{HHT}),(\mathrm{HTT})\} \\ &\mathrm{A} \cap \mathrm{B}=\{(\mathrm{HTH}),(\mathrm{THH}),(\mathrm{HHT})\} \end{aligned}

P(A)=4

P(B)=7

Required Probability =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{3}{7}

 

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