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Explain solution RD Sharma class 12 chapter Probability exercise 30.6 question 8 maths

Answers (1)

Answer:

 \frac{83}{150}

Hint:

 To solve this we use total probability formula.

Given:

 Bag A contains 8 white and 7 black balls & Bag B contains 5 white and 4 black balls

Solution:

E1 = Black ball transfer from Bag A to Bag B

E2 = White ball transfer from Bag A to Bag B

A = White ball drawn

\begin{aligned} &P(E_1)=\frac{7}{15} \qquad ; \qquad P(E_2)=\frac{8}{15}\\ &P\left (\frac{A}{E_1} \right )=\frac{5}{10} \qquad ; \qquad P\left (\frac{A}{E_2} \right )=\frac{3}{5} \end{aligned}

Using total probabilty theorem

\begin{aligned} &\text { required probability }=P(E_1)\times P\left (\frac{A}{E_1} \right )+ P(E_2)\times P\left (\frac{A}{E_2} \right )\\ &=\frac{7}{15}\times \frac{5}{10}+\frac{8}{15}\times \frac{3}{5}\\ &=\frac{7}{30}+\frac{8}{25}\\ &=\frac{83}{150} \end{aligned}

Posted by

Gurleen Kaur

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