Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (iii).

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (iii).

Answers (1)

Answer : =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{6}{7}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given,

            A=At most two tails

            B=At least one tail

Solution:

Clearly,

\begin{aligned} &S=\{(H H H),(H H T),(H H T),(T T H),(T T T),(H T H),(T H H),(T T H)\} \\ &A=\{(\pi H),(T H H),(\mathrm{HHT}),(T H T),(\mathrm{HHT}),(\mathrm{HTT}),(\mathrm{HHH})\} \\ &\mathrm{B}=\{(\mathrm{TT}),(\mathrm{TH}),(\mathrm{THH}),(\mathrm{HHT}),(\mathrm{THT}),(\mathrm{HHT}),(\mathrm{HTT})\} \end{aligned}

Now, \mathrm{A} \cap \mathrm{B}=\{(\mathrm{TTH}),(\mathrm{THH}),(\mathrm{HHT}),(\mathrm{HTT})\}

P(A) = 7
P(B) = 7

Required Probability =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{6}{7}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question