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Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (i).

Answers (1)

Answer: \frac{1}{2}

Hint: \text{Probability}=\frac{\text{No. of Outcomes}}{\text{Total no of outcomes}}

Given, A=Heads on third toss              

            B=Heads on first two tosses

Solution:

\begin{aligned} &S=\{(H H H),(H H T),(H H T),(T T H),(T T T),(H T H),(T H H),(T T H)\} \\ &A=\{(H H H),(H T H),(T H H),(T T H)\} \\ &B=\{(H H H),(H H T)\} \\ &A \cap B=\{H H H\} \end{aligned}

P(A)=4, P(B)=2, P(A \cap B)=1

 Required Probability =P\left (\frac{A}{B} \right )

 \begin{aligned} &=\frac{P(A \cap B)}{P(B)} \\ &=\frac{1}{2} \end{aligned}                       

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