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please solve RD sharma class 12 chapter 30 Probablity Exercise very short answer question, question 4 maths textbook solution

Answers (1)

The required probability is \frac{5}{6^{4}}

Hint:

P(Getting\; three\; number\; that\; are\; consecutive) = \frac{Total\; number \;of \;favorable \;outcome}{Total \;number\; of \;sample \;space}

Given:

Three numbers are chosen at random from 1 to 20.

Explanation:

Let S be a sample space. A cube has 6 faces

Total Possible Outcomes in 5 throws = 6^{5}

So n(S)=6^{5}

Let A be any event of getting 7 is by getting two 2’s and one 3’s

n(A)=\frac{5_{P_{3}}}{2!}\\ =\frac{5 \times 4\times3\times2\times1}{3\times2\times1}\times\frac{1}{2\times1}\\ =30

P(A)=\frac{n(A)}{n(S)}\\ =\frac{30}{6_{5}}\\ =\frac{5}{6^{4}}

Thus , The required probability is \frac{5}{6^{4}}

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