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Need solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 26.

Answers (1)

Answer: \frac{4}{7}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given:

Total Possibility of cards = {1,2,3,4,5,6,7,8,9,10}

Solution:

Let       A = An even number on the card

            B = A number more than 3 on the card.

\begin{aligned} &A=\{2,4,6,8,10\} \\ &B=\{4,5,6,7,8,9,10\} \\ &A \cap B=\{4,6,8,10\} \end{aligned}
P(A) = {5}
P(B) = {7}
 

Required probability P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{4}{7}

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