Need solution for RD Sharma Maths Class12 Chapter 30 Probability Exercise Fill in the Blanks Question, Question 12.

Answers (1)

Answer:   P(A)+P(B)-2P(A\cap B)

Given:

If A and B are two everts, then the provability of occurrence of exactly one of A and B is equal to ...

Hint:

P(A\cap B)=P(A)-P(A\cap B)

Explanation:

Exactly one of the events of ε;A and B is represented by A\cap B+A\cap B

Hence ,

\begin{aligned} \mathrm{P}(A \cap \bar{B})+P(\bar{A} \cap B) &=[P(A)-P(A \cap B)]+[P(B)-P(A \cap B)] \\ &=P(A)+P(B)-2 P(A \cap B) \end{aligned}

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