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Please solve RD Sharma Class 12 Chapter 30 Probability Exercise Case Study Based  Question, question 2 sub question (iv) Maths textbook solution.

Answers (1)

Answer:

            (b)

Hint:

            You must know rules of conditional probability

Given:

            6% people are left handed with blood group O, 10% of those with other blood group are left handed, 30% of people have blood group O

Solution:

E_1= The people selected is of blood group O

E_2= The people selected is of other than blood group O

E= Selected person is left handed

\begin{aligned} &P\left(E_{1}\right)=0.3 \\ &P\left(E_{2}\right)=0.7 \\ &P\left(\frac{E}{E_{1}}\right)=0.06 \\ &P\left(\frac{E}{E_{2}}\right)=0.1 \end{aligned}

If person is selected at random, probability that he/she has blood group O

Using Baye’s theorem,

P\left(\frac{E_{1}}{E}\right)=\frac{P\left(E_{1}\right) \cdot P\left(\frac{E}{E_{1}}\right)}{P\left(E_{1}\right) \cdot P\left(\frac{E}{E_{1}}\right)+P\left(E_{2}\right) \cdot P\left(\frac{E}{E_{2}}\right)}

\begin{aligned} &=\frac{0.3 \times 0.06}{0.03 \times 0.06+0.7 \times 0.1} \\ &=\frac{0.018}{0.018 \times 0.07} \\ &=\frac{9}{44} \end{aligned}

So, (b) is correct answer

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