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  • please solve RD sharma class 12 chapter 30 Probablity Exercise very short answer question, question 3 maths textbook solution

please solve RD sharma class 12 chapter 30 Probablity Exercise very short answer question, question 3 maths textbook solution

Answers (1)

The probability that the number has same digit is  \frac{1}{25}

Hint:

Three digit number cannot start with 0 , and hundredth place can have any of the 4 digits.

Given:

Given digits are 0,2,4,6 and 8 . We have to form a number using digits 0,2,4, 6 and 8 .

Explanation:

Since a three digit number cannot begin with the digit 0. The hundredth place can have any of the 4 digits. Also tens & units place can have all the 5 digits.

So S = total possibilities for 3 -digit numbers

n(S) = 4 \times 5 \times 5=100

Let A be the event of three digit numbers having all digits same =4
nA=4

Thus,

PA=\frac{n(A)}{n(S)}\\ =\frac{4}{100}\\ =\frac{1}{25}

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