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Please solve RD Sharma class 12 chapter Probability exercise 30.7 question 17 maths textbook solution

Answers (1)

Answer:

 \frac{3}{7}

Hint:

 Use Bayes theorem.

Given:

 The first plant manufacture 60% of bicycle and second plant 40% out of that 80% of bicycle are rated of standard quality at first plant and 90% of standard quality at second plant.

Solution:

E1 be event of cycle is from first plant

E2 be event of second plant

A be event the cycle is standard

\begin{aligned} &P(E_1)=0.6\\ &P(E_2)=0.4\\ &P\left ( \frac{A}{E_1} \right )=0.8\\ &P\left ( \frac{A}{E_2} \right )=0.9\\ \end{aligned}

Using Baye’s theorem we get

\begin{aligned} &P\left (\frac{E_2}{A} \right )=\frac{P(E_2).P\left ( \frac{A}{E_2} \right )}{P(E_1)\times P\left ( \frac{A}{E_1} \right )+P(E_2)\times P\left ( \frac{A}{E_2} \right )}\\ &=\frac{0.4\times 0.9}{0.6\times 0.8+0.4\times 0.9}\\ &=\frac{0.36}{0.84}\\ &=\frac{36}{84}\\ &=\frac{9}{21}=\frac{3}{7} \end{aligned}

Posted by

Gurleen Kaur

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