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Explain solution RD Sharma Class 12 Chapter 20 Areas of Bounded Regions exercise 20.3 question 31 Maths.
 

Answers (1)

Answer:

\frac{11}{6}\text{sq. units}

Hint:

Use concept.

Given:

The given equation are y =x and y =x^2+2 .

Solution:  To find area bounded by x =0, x =1

and

y =x        ........(1)

y =x^2+2........(2)

Equation(1)  is a line passing through (2,2) and (0,0).Equation (2) is a parabola upward with vertex at (0,2).

A rough sketch of curve is as under:

Shaded region is sliced into rectangle of area=. .It slides from to ,so

Required Area=Region OABCO

\begin{aligned} A &=\int_{0}^{1}\left(y_{1}-y_{2}\right) d x \\ &=\int_{0}^{1}\left(x^{2}+2-x\right) d x \\ &=\left[\frac{x^{3}}{3}+2 x-\frac{x^{2}}{2}\right]_{0}^{1} \\ &=\left[\left(\frac{1}{3}+2-\frac{1}{2}\right)-0\right] \\ &=\left(\frac{2+12-3}{6}\right) \\ &=\frac{11}{6} \text { sq.units } \end{aligned}

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