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  • Need solution for RD sharma maths class 12 chapter 20 Areas Of Bounded Region exercise Fill in the blanks question 11

Need solution for RD sharma maths class 12 chapter 20 Areas Of Bounded Region exercise Fill in the blanks question 11

Answers (1)

best_answer

1 sq.units

Hint:

Use this formula to integrate : \int\sin x \;\; dx =-\cos x+c

Given:

y=\sin x,x=0,x=\frac{\pi}{2},x-axis

Explanation:
Area =\int_{0}^{\frac{\pi}{2}}\sin x \;\;dx

=[-\cos x]_{0}^{\frac{\pi}{2}}\\ =-\cos \frac{\pi}{2}+\cos 0\\

=1 sq. units\;\;\;\;\;\;\; \left [\because \int \sin x\;\; dx=-\cos x+c \right ]

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