Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma class 12 chapter 20 Areas of Bounded Regions exercise multiple choice question 17 maths textbook solution

Please solve RD Sharma class 12 chapter 20 Areas of Bounded Regions exercise multiple choice question 17 maths textbook solution

Answers (1)

Answer:

 (b)

Hint:

 Integration

Given:

 \text { The ratio of } y=cos\, x \text { and } y=cos2x \text { from } x=0 \text { to }x=\frac{\pi }{3}

Explanation:

\begin{aligned} &\text {Area of }cos\, x=A_{1}=\int_{0}^{\frac{\pi }{3}}cos\, xdx\\ &=\left [ sin\, x \right ]_{0}^{\frac{\pi }{3}}\\ &=sin\frac{\pi }{2}-sin\, 0\\ &=\frac{\sqrt{3}}{2} \end{aligned}

\begin{aligned} &\text {Area of }cos\, 2x=A_{2}=\int_{0}^{\frac{\pi }{3}}cos\, 2xdx\\ &=sin\frac{2\pi }{3}-sin\, 0\\ &=\frac{1}{2}sin\left ( \pi -\frac{\pi }{3} \right )-0\\ &=sin\frac{\pi }{3}\\ &=\frac{\frac{\sqrt{3}}{2}}{2}\\ &=\frac{\sqrt{3}}{4} \end{aligned}

\begin{aligned} &A_{1}:A_{2}=\frac{\left ( \frac{\sqrt{3}}{2} \right )}{\left ( \frac{\sqrt{3}}{4} \right )}=2:1 \end{aligned}

Posted by

Gurleen Kaur

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Board Exam Date Sheet 2025: CBSE, UPMSP, MPBSE, Class 10, 12 board exam dates out; BSEB, CGBSE schedules soon
anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers
anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4

Latest Question