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Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 51

Answers (1)

Answer:

Max Profit = Rs.1, 36,000 when 40 first class tickets and 160 economy class tickets are sold.

Hint:

Form Linear Equation and solve graphically.

Given:

An aero plane can carry a maximum of 200 passengers. A profit of Rs.1000 is made on each first class ticket and a profit of Rs.600 is made on each economy class ticket. The airline reserves at least 20 seats of first class. However, at least 4 times as many passengers prefer to travel by economy class to the first class.

Solution:

Let required number of first class and economy class tickets be x and y respectively.

Each ticket of first class and economy class make profit of Rs.1000 and Rs.600 respectively.

So, x ticket of first class and y tickets of economy class make profit of Rs.1000x and Rs.600y respectively.

Let total profit be Z=1000x+600y

Given, aero plane can carry a minimum of 200 passengers, so x+y \leq 200

Given, airline reserves at least 20 seats for first class, so x \geq 20

Also, at least 4 times as many passengers prefer to travel by economy class to the first class, so

                y \geq 4 x

Hence the mathematical formulation of the LPP is

Max Z = 1000x+600y

Subject to constraints

                \begin{aligned} &x+y \leq 200 \\ & \end{aligned}        

                x \geq 20 \text { And } y \geq 4 x \\

x, y \geq 0 {Seats in both the classes cannot be 0}

 

The feasible region determined by the given constraints can be diagrammatically represented as.

 

The corner points are A(20,80), B(40,160), C(20,180)

 

The values of Z at these corner as follows

Corner Points

z=1000x+600y

O

0

A

68000

B

136000(maximum)

C

128000

The maximum value of Z is attained at B(40,160).

Thus, the max profit is Rs.136000 obtained when 40 first class tickets and 160 economy class tickets sold.

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