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  • Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.1 question 7

Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.1 question 7

Answers (1)

Answer:    Mini z=60 x+100 y
                Sub to

\begin{aligned} &10 x+5 y \geq 20 \\\\ &5 x+4 y \geq 20 \\\\ &2 x+6 y \geq 13 \\\\ &x \geq 0, y \geq 0 \end{aligned}

Hint:          Let x and y  in given condition.

Given:      

\begin{array}{|l|l|l|l|} \hline & \text { Food I } & \text { Food II } & \begin{array}{l} \text { Minimum daily } \\ \text { requirement for the } \\ \text { nutrient } \end{array} \\ \hline \text { Calcium } & 10 & 5 & 20 \\ \hline \text { Protein } & 5 & 4 & 20 \\ \hline \text { Calory } & 2 & 6 & 13 \\ \hline \text { Price(?) } & 60 & 100 & \\ \hline \end{array}

Solution:   Let x  diet consist of Food I.

y diet consist of Food II.

Objective function:

Mini z=60 x+100 y

                Sub to
\begin{aligned} &10 x+5 y \geq 20 \\\\ &5 x+4 y \geq 20 \\\\ &2 x+6 y \geq 13 \\\\ &x \geq 0, y \geq 0 \end{aligned}

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