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  • Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.2 question 19

Need solution for RD Sharma maths class 12 chapter Linear Programming exercise 29.2 question 19

Answers (1)

Answer: the maximum value of Z is 3

Hint: Plot the points on the graph

Given: ? =x+y

Solution: We need to maximize ? =x+y . First, we will convert the given equations, awe obtain the following equations;

                -2 x+y=1, x=2, x+y=3, u=0, y=0

The line -2 x+y=1  meets the coordinates axis at A\left(-\frac{1}{2}, 0\right) \text { and } B(0,1). Join these points to obtain the line -2 x+y=1 . Clearly (0, 0), satisfies the equations -2 x+y \leq 1  . So the region xy-plane that

contains the origin represents the section set of the given equation.

U=2 , is the line passing through (2,0) and parallel to the y-axis. The region below the line u=2 will satisfy the given equation.

The line x+y=3 meets the coordinates axis at c(3, 0) . clearly, (0, 0) satisfies the equation x+y \leq 3 . So the region xy-plane that contains the origin represents the solution set of the given equation

Region represented by u \geq 0 \text { and } y \geq 0 . Since every point in the first quadiant satisfies the equation, so the first quadrant is the region represented by the inequalities

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