Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 55

Explain solution RD Sharma class 12 Chapter 29 Linear Programming exercise 29.4 question 55

Answers (1)

Answer: Maximum Z=100x+300y is the required LPP.

Hint:

 Use property of LPP

Given:

The maximum number of hours available per day is16, If the profit on a necklace is Rs.100 and the bracelet is Rs.300

Solution:

Let the number of necklaces manufacturer be x and the number of bracelets manufacture be y.

Since the total number of item are at most 24.

       x+y \leq 24                                    … (i)

Bracelets take 1 hour to manufacture and necklaces take half an hour to manufacture.

X item take x hour to manufacture and y item take y/2 hours to manufacture and maximum time available is 16 hours

Therefore,

      \frac{x}{2}+y \leq 16                                    … (ii)

The profit on one necklace is Rs.100 and the profit on one bracelet is Rs.300.

Let the profit be Z. Now we wish to maximize the profit.

So,

     Maximize Z=100x + 300y          … (iii)

So,

       \begin{aligned} &x+y \leq 24 \\ &\frac{x}{2}+y \leq 16 \end{aligned}

Maximize Z = 100x + 300y is required LPP

X+y=24

 

Corner points

Max Z

(0,16)

1800

(24,0)

2400

(16,18)

7000

 

           The maximum value of Z = 7000 at (16,18)

Posted by

infoexpert27

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE board exams 2025 from February 15; Class 10, 12 subject-wise marks distribution
anam-khan

CBSE Date Sheet 2025: Class 10, 12 board exam dates soon on cbse.gov.in; previous trends, sample papers
anam-khan

CBSE Board Exams 2025: 75% attendance must for students to be eligible, reiterates board

Latest Question