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  • Need solution for RD Sharma maths class 12 chapter 20 Areas of Bounded Regions exercise multiple choice question 23

Need solution for RD Sharma maths class 12 chapter 20 Areas of Bounded Regions exercise multiple choice question 23

Answers (1)

Answer:

 (c)

Hint:

 Integration

Given:

\text { Area }=(b-1)sin(3b+4)\\ x=1,\: x=b 

Explanation:

\begin{aligned} &\text { Area }=\int_{1}^{b}f(x)dx\\ &(b-1)sin(3b+4)=\int_{1}^{b}f(x)dx \end{aligned}

Differentiate both sides with respect to b,

\begin{aligned} &f(b)=3(b-1)cos(3b+4)+sin(3b+4)\\ &\text { Put } b=x\\ &f(x)=3(x-1)cos(3x+4)+sin(3x+4) \end{aligned}

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Gurleen Kaur

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