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Need solution for rd sharma maths class 12 chapter 24 vector or cross product Exercises Multiple choice questions question 12 maths textbook solution

Answers (1)

Answer: 20

Given:\left | \overrightarrow{a}\times \overrightarrow{b} \right |=4\left | \overrightarrow{a}\overrightarrow{b} \right |=2

Hint: Using

              \left | \overrightarrow{a}\times \overrightarrow{b} \right |=\left | \overrightarrow{a} \right |\left | \overrightarrow{b} \right |\sin \theta ;

              \left | \overrightarrow{a}. \overrightarrow{b} \right |=\left | \overrightarrow{a} \right |\left | \overrightarrow{b} \right |\cos \theta

Explanation:

              \left | \overrightarrow{a}\times \overrightarrow{b} \right |=4

              \left | \overrightarrow{a} \right |\left | \overrightarrow{b} \right |\sin \theta=4                              ……………………. (1)

Also      \left | \overrightarrow{a}.\overrightarrow{b} \right |=2

             \left | \overrightarrow{a} \right |\left | \overrightarrow{b} \right |\cos \theta=2                              ……………………. (2)

Squaring and adding (1) and (2)

              \begin{aligned} &|\vec{a}|^{2}|\vec{b}|^{2} \sin ^{2} \theta+|\vec{a}|^{2}|\vec{b}|^{2} \cos ^{2} \theta=(4)^{2}+(2)^{2} \\ &\end{aligned}

              |\vec{a}|^{2}|\vec{b}|^{2}\left(\sin ^{2} \theta+\cos ^{2} \theta\right)=16+4                                 \quad\left[\sin ^{2} \theta+\cos ^{2} \theta=1\right] \\

             |\vec{a}|^{2}|\vec{b}|^{2}(1)=20 \\

            |\vec{a}|^{2}|\vec{b}|^{2}=20

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