Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Please solve RD Sharma Class 12 Chapter 24 Vector or Cross Product Exercise Very Short Answer Question, question 8 Maths textbook solution.

Please solve RD Sharma Class 12 Chapter 24 Vector or Cross Product Exercise Very Short Answer Question, question 8 Maths textbook solution.

Answers (1)

ANSWER:

\theta=\frac{\pi}{4} \text { or }\left(\pi-\frac{\pi}{4}\right) \cong \frac{3 \pi}{4}

HINT:

 Just use the formula of cross product .

GIVEN:

\overrightarrow{a} and \overrightarrow{b} be  two vectors  having magnitude  3 and \frac{\sqrt{2}}{3}

SOLUTION:

i.e, \left | \overrightarrow{a} \right | =3

\left | \overrightarrow{b} \right |=\frac{\sqrt{2}}{3}

Moreover, \overrightarrow{a} \times \overrightarrow{b} is a unit vector

\begin{aligned} &\therefore \vec{a} \times \vec{b}=1 \\ &\therefore \vec{a} \times \vec{b}=|\vec{a}||\vec{b}| \operatorname{Sin} \theta \cdot \widehat{n} \end{aligned}

1=3\left(\frac{\sqrt{2}}{3}\right) \operatorname{\sin} \theta \cdot(1)

\sin \theta = \frac{1}{\sqrt{2}}

\theta=\frac{\pi}{4} \text { or }\left(\pi-\frac{\pi}{4}\right) \cong \frac{3 \pi}{4}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers
anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4
anam-khan

When will CBSE Board exam 2025 date sheet be released for Class 10, 12?

Latest Question