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  • Need solution for RD Sharma Maths Class 12 Chapter 24 Vector Or Cross Product Exercise Very Short Answer Question, question 25.

Need solution for RD Sharma Maths Class 12 Chapter 24 Vector Or Cross Product Exercise Very Short Answer Question, question 25.

Answers (1)

ANSWER:

\frac{\pi}{3}

HINT:

Just use the formula of cross product

GIVEN:

|\vec{a}|=\sqrt{3} \quad|\vec{b}|=\frac{2}{3}

SOLUTION:

\begin{aligned} |\vec{a} \times \vec{b}| &=|\vec{a}||\vec{b}| \sin \theta \\ 1 &=(\sqrt{3})\left(\frac{2}{3}\right) \sin \theta \quad[\because|\vec{a} \times \vec{b}| \text { is a Unit vector] } \end{aligned}

\begin{gathered} \frac{3}{2 \times \sqrt{3}}=\sin \theta \\ \frac{\sqrt{3} \times \sqrt{3}}{2 \times \sqrt{3}}=\sin \theta \end{gathered}

\therefore \sin =\frac{\sqrt{3}}{2}

\therefore \theta =\frac{\pi}{3}

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