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Need solution for RD Sharma Maths Class 12 Chapter 24 Vector Or Cross Product Exercise Very Short Answer Question, question 23.

Answers (1)

ANSWER:

-\overrightarrow{c}

HINT: A unit vector perpendicular to two vector \overrightarrow{a} and \overrightarrow{b}   is  \pm \frac{(\vec{a} \times \vec{b})}{|\vec{a} \times \vec{b}|}

GIVEN: \overrightarrow{a} and \overrightarrow{b} 

SOLUTION:

If  \overrightarrow{c}=\overrightarrow{a}\times \overrightarrow{b}

Multiplying (-1) on both sides

\begin{aligned} &-\vec{c}=-(\vec{a} \times \vec{b}) \\ &-\vec{c}=-\vec{b} \times(\vec{a}) \quad[\because(\vec{a} \times \vec{b})==(\vec{b} \times \vec{a})] \end{aligned}

\therefore -\overrightarrow{c} is another vector perpendicular to \overrightarrow{a} and \overrightarrow{b} 

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