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Need solution for RD Sharma Maths Class 12 Chapter 24 Vector Or Cross Product Exercise Very Short Answer Question, question 27.

Answers (1)

ANSWER:

  6 sq. unit

HINT: Cross product both vectors to obtain Area of parallelogram.

GIVEN:

Two vectors,2\widehat{i} and 3\widehat{j}

SOLUTION:

 Let,

\begin{aligned} &\vec{a}=2 \hat{i}+0 \hat{j}+0 \hat{k} \\ &\vec{b}=0 \hat{i}+3 \hat{j}+0 \hat{k} \end{aligned}

Area of parallelogram 

\begin{aligned} \therefore \hat{a} \times \hat{b} &=\left|\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k} \\ 2 & 0 & 0 \\ 0 & 3 & 0 \end{array}\right| \\ &=\hat{i}(0-0)-\hat{j}(0-0)+\hat{k}(6-0) \\ &=6 \hat{k} \\ &=6 \text { Sq Units } \end{aligned}

Area = \left | \widehat{a}\times \widehat{b} \right |=\sqrt{6^2}=6 \; \text{sq.units}

 

 

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