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  • Explain solution RD Sharma class 12 chapter Vector or Cross Product exercise 24.1 question 16 maths

Explain solution RD Sharma class 12 chapter Vector or Cross Product exercise 24.1 question 16 maths

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 Answer        : \frac{\pi }{6}

Hint               : To solve this we use |\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta  formula

Given             : \vec{a} \times \vec{b}=3 \hat{\imath}+2 \hat{\jmath}+6 \hat{k}

Solution        : |\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta

\begin{gathered} \sqrt{3^{2}+2^{2}+6^{2}}=2 \times 7 \sin \theta \\\\ \sqrt{9+4+12}=14 \sin \theta \\\\ 7 =14 \sin \theta \end{gathered}

                \begin{aligned} \sin \theta &=\frac{1}{2} \\\\ \theta &=\frac{\pi}{6} \end{aligned}

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