Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma Maths Class 12 Chapter 24 Vector or Cross Product exercise Very Short Answer Question, question 11.

Provide solution for RD Sharma Maths Class 12 Chapter 24 Vector or Cross Product exercise Very Short Answer Question, question 11.

Answers (1)

ANSWER:

  \theta = \frac{\pi}{3}

HINT:

Just apply the formula of cross product and dot product.

GIVEN:

  \begin{gathered} \vec{a} \times \vec{b}=\sqrt{3} \\ \vec{a} \cdot \vec{b}=1 \end{gathered}

SOLUTION:    

\begin{aligned} \vec{a} \times \vec{b} &=\sqrt{3} \\ \vec{a} \cdot \vec{b} &=1 \\ \text { Using }|\vec{a} \times \vec{b}| &=|\vec{a}||\vec{b}| \sin \theta \\ \sqrt{3} &=|\vec{a}||\vec{b}| \operatorname{sin} \theta \\ \therefore \frac{\sqrt{3}}{\operatorname{sin} \theta} &=|\vec{a}||\vec{b}| \ldots \ldots .....(1) \end{aligned}

\begin{aligned} \text { Using } \vec{a} \cdot \vec{b} &=|\vec{a}||\vec{b}| \cos \theta \\ 1 &=|\vec{a}||\vec{b}| \cos \theta \\ \therefore \frac{1}{\operatorname{cos} \theta} &=|\vec{a}||\vec{b}| \ldots \ldots ......(2) \end{aligned}

From (1) and (2)

\begin{aligned} \frac{\sqrt{3}}{\operatorname{sin} \theta} &=\frac{1}{\operatorname{cos} \theta} \\ \therefore \sqrt{3} &=\frac{\operatorname{sin} \theta}{\operatorname{cos} \theta} \\ \sqrt{3} &=\tan \theta \end{aligned}

\therefore \theta =\frac{\pi}{3}

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE practical exams 2026 will be cancelled over non-compliance with guidelines, says board

Latest Question