Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD sharma class 12 chapter 24 Vector or cross product exercise Fill in the blanks question 11

Explain solution RD sharma class 12 chapter 24 Vector or cross product exercise Fill in the blanks question 11

Answers (1)

best_answer

\therefore \theta=\frac{\pi}{6}

Hint: Use formula of dot product &cross product & then compare

Given:

\begin{aligned} &|\vec{a} \times \vec{b}|=1 \\ &|\vec{a} \cdot \vec{b}|=\sqrt{3} \end{aligned}

If

\begin{aligned} &|\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta \\ &1=|\vec{a}||\vec{b}| \sin \theta \\ &\frac{1}{\sin \theta}=|\vec{a}||\vec{b}| \ldots \ldots .(1) \\ \end{aligned}

\begin{aligned} &|\vec{a} \cdot \vec{b}|=|\vec{a}||\vec{b}| \cos \theta \\ &\sqrt{3}=|\vec{a}||\vec{b}| \cos \theta \\ &\frac{\sqrt{3}}{\cos \theta}=|\vec{a}||\vec{b}| \ldots \ldots . .(2) \end{aligned}

From (1) &(2)

\begin{aligned} &\frac{1}{\sin \theta}=\frac{\sqrt{3}}{\cos \theta} \\ &\frac{1}{\sqrt{3}}=\frac{\sin \theta}{\cos \theta} \\ &\frac{1}{\sqrt{3}}=\tan \theta \end{aligned}

Posted by

Info Expert 29

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE 12th Result 2026: Board refutes OSM glitch claims, says Class 12 results likely in third week of May
anam-khan

CBSE 12th Result 2026 LIVE: Class 12 scores soon at cbse.gov.in, how to check, digilocker, pass percentage
anam-khan

CBSE 12th Result 2026 Date LIVE: Class 12 marksheet on cbse.gov.in, DigiLocker soon; OSM system, passing marks

Latest Question