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  • Explain solution RD Sharma class 12 chapter Probability exercise 30.6 question 4 maths

Explain solution RD Sharma class 12 chapter Probability exercise 30.6 question 4 maths

Answers (1)

Answer:

 \frac{7}{15}

Hint:

 To solve this we use only white balls and then total probability formula

Given:

 A bag contains 3 white and 2 black balls and another bag contains 2 white and 4 black balls.

Solution:

Bag 1 → 3W + 2B = 5            Bag 2 → 2W + 4B = 6

\begin{aligned} &P(\text { Choosing a bag })=\frac{1}{2}\\ &P(\text { Bag 1 })=P(\text { Bag 2 })=\frac{1}{2}\\ &\text { Bag 1 }= \text { White ball }\\ &P(W_1)=\frac{\text { Number of white balls }}{\text { Total Number of balls }}=\frac{3}{5}\\ &\text { Bag 2 }= \text { White ball }\\ &P(W_1)=\frac{\text { Number of white balls }}{\text { Total Number of balls }}=\frac{2}{6}=\frac{1}{3}\\ &P(W)=\frac{1}{2}\times \frac{3}{5}=\frac{3}{10} \dots \dots \text { probability of drawing white ball from Bag 1 }\\ &P(W)=\frac{1}{2}\times \frac{1}{3}=\frac{1}{6} \dots \dots \text { probability of drawing white ball from Bag 2 }\\ &\text { Total probability }=\frac{3}{10}+\frac{1}{6}=\frac{9+5}{30}=\frac{14}{30}=\frac{7}{15} \end{aligned}

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Gurleen Kaur

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