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Please solve RD Sharma class 12 chapter Probability exercise 30.6 question 9 maths textbook solution

Answers (1)

Answer:

 \frac{31}{72}

Hint:

 To solve this we find probability of white ball

Given:

 Bag I contains 4 white and 5 black balls & Bag II contains 3 white and 4 black balls

Solution:

E1 = Black ball transfer from first to second bag

E1 = White ball transfer from first to second bag

A = White ball drawn

\begin{aligned} &P(E_1)=\frac{5}{9} \qquad ; \qquad P(E_2)=\frac{4}{9}\\ &P\left (\frac{A}{E_1} \right )=\frac{3}{8} \qquad ; \qquad P\left (\frac{A}{E_2} \right )=\frac{4}{8} \end{aligned}

Using total probabilty theorem

\begin{aligned} &\text { Required probability }=P(E_1)\times P\left (\frac{A}{E_1} \right )+ P(E_2)\times P\left (\frac{A}{E_2} \right )\\ &=\frac{5}{9}\times \frac{3}{8}+\frac{4}{9}\times \frac{4}{8}\\ &=\frac{15}{72}+\frac{2}{9}\\ &=\frac{15+16}{72}\\ &=\frac{31}{72} \end{aligned}

Posted by

Gurleen Kaur

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