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  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 11.

Answers (1)

Answer: 1,\frac{1}{2}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given, A= Son standing on one end

            B= Father standing in the middle

Solution:

Clearly,

  S=Total events

   \begin{aligned} &=\{\mathrm{MFS}, \mathrm{MSF}, \mathrm{FSM}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{A}=\{\mathrm{MFS}, \mathrm{FMS}, \mathrm{SMF}, \mathrm{SFM}\} \\ &\mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \\ &\mathrm{A} \cap \mathrm{B}=\{\mathrm{MFS}, \mathrm{SFM}\} \end{aligned}

(1) 

\begin{gathered} P\left(\frac{A}{B}\right)=\frac{n(A \cap B)}{n(B)} \\ =\frac{2}{2} \\ =1 \end{gathered}

(2)

\begin{gathered} P(B \mid A)=\frac{P(A \cap B)}{P(A)} \\ =\frac{2}{4} \\ =\frac{1}{2} \end{gathered}

 

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