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  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 13.

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 13.

Answers (1)

Answer: \frac{1}{6}

Hint: \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

 

Solution:

Clearly,
\begin{aligned} &A=\left\{\begin{array}{l} (1,4),(2,4),(3,4), \\ (4,4),(5,4),(6,4) \end{array}\right\} \\ &B=\{(4,4),(3,5),(5,3),(2,6),(6,2)\} \\ &A \cap B=\{(4,4)\} \end{aligned}            

 

Required Probability =  P(B \mid A)=\frac{P(A \cap B)}{P(A)}=\frac{1}{6}

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