Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (ii).

Provide solution for RD Sharma Maths Class 12 Chapter 30 Probability Exercise 30.3 question 8 sub question (ii).

Answers (1)

Answer: =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{3}{7}

 Hint:  \text{Probability}=\frac{\text{No. of outcomes}}{\text{Total no.of Outcomes }}

Given, A=At least two heads

            B=At most two heads

Solution:

Clearly, 

S=\{(H H H),(H H T),(H H T),(T T H),(T T T),(H T H),(T H H),(T T H)\}

\begin{aligned} &\mathrm{A}=\{(\mathrm{HHH}),(\mathrm{HTH}),(\mathrm{THH}),(\mathrm{HHT})\} \\ &\mathrm{B}=\{(\mathrm{TT}),(\mathrm{HTH}),(\mathrm{HTT}),(\mathrm{THT}),(\mathrm{THH}),(\mathrm{HHT}),(\mathrm{HTT})\} \\ &\mathrm{A} \cap \mathrm{B}=\{(\mathrm{HTH}),(\mathrm{THH}),(\mathrm{HHT})\} \end{aligned}

P(A)=4

P(B)=7

Required Probability =P\left(\frac{A}{B}\right)=\frac{P(A \cap B)}{P(B)}=\frac{3}{7}

 

Posted by

infoexpert24

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Less bias, more risk? CBSE on-screen marking system leaves Class 12 students, teachers cautious but optimistic
anam-khan

CBSE Plans: Compulsory computing, AI in Classes 9, 10 syllabus; more skill subjects; 25% EWS quota review
anam-khan

CBSE Board 2026 Exam LIVE: 12th engineering graphics, cost accounting exams over; OSM, paper pattern

Latest Question