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Explain solution RD Sharma class 12 chapter Vector or Cross Product exercise 24.1 question 16 maths

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 Answer        : \frac{\pi }{6}

Hint               : To solve this we use |\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta  formula

Given             : \vec{a} \times \vec{b}=3 \hat{\imath}+2 \hat{\jmath}+6 \hat{k}

Solution        : |\vec{a} \times \vec{b}|=|\vec{a}||\vec{b}| \sin \theta

\begin{gathered} \sqrt{3^{2}+2^{2}+6^{2}}=2 \times 7 \sin \theta \\\\ \sqrt{9+4+12}=14 \sin \theta \\\\ 7 =14 \sin \theta \end{gathered}

                \begin{aligned} \sin \theta &=\frac{1}{2} \\\\ \theta &=\frac{\pi}{6} \end{aligned}

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