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Provide solution for RD Sharma maths class 12 chapter Vector or Cross Product exercise 24.1 question 14

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Answer         :\frac{\pi }{4}

Hint               : To solve this equation we use aband |\vec{a}||\vec{b}| \text { and }|\vec{a} \times \vec{b}|

Given            : |\vec{a} \times \vec{b}|=\vec{a} \cdot \vec{b}

Solution        :

                        1)\vec{a} \times \vec{b}|=|a||b| \cos \theta\\

                        2) \vec{a} \cdot \vec{b}|=|a||b| \sin \theta

\Rightarrow|\vec{a}||\vec{b}| \cos \theta=|\vec{a}||\vec{b}| \sin \theta

\begin{aligned} &\Rightarrow \frac{\sin \theta}{\cos \theta}=1 \\\\ &\Rightarrow \tan \theta=1 \\\\ &\Rightarrow \theta=\tan ^{-1} 1 \\\\ &\theta=\frac{\pi}{4} \end{aligned}

 

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